April is my last month with HAVAmedia, thank you for the past 7 years!


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Excalibur Gift Code Giveaway [ENDED]


It's a gifting spree! Gabe at R2Games has sent us a package of gift codes for their new mobile MMORPG "Excalibur".

The game itself is free! Each gift code contains 500,000 Gold (in-game money) and 300 Luna (points used to increase stats).

How to get a code:
1) Comment on this blog post

2) Wait for the code to arrive in your N4G inbox.

*This blog post will be updated when all codes are gone*
About Excalibur

Set in the realm of King Arthur and the Knights of the Round Table, Excalibur combines a mix of
MMORPG and classic beat ‘em up features. Players experience thrilling combat and immersive
story at their fingertips with a choice of four unique classes: Wizards, Knights and Assassins

(Archers coming soon!)

Excalibur – Gift Code Redeeming Instructions

In the main game screen, tap the “Reward” button on the top of the screen, then tap the “Gifts”
tab. Input the code in the Gift Pack Code box and hit the “Claim” button. The items will appear
in your Pack (Inventory), simply “Use” them from there to activate them. (If you can’t see the
“Pack” button at the bottom of the screen, tap the plus sign button on the bottom right of the
screen to reveal more menus).

Note: The “Reward” button only appears after completing a main quest showing you how PvP
works, around level 10. If you haven’t unlocked the Reward button yet, simply keep playing a

1GHz or higher CPU
Android version 2.1 or higher
512MB RAM or higher
50MB free hard drive space
250MB or more free SD card space
OpenGL ES 2.0 GPU or better

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zerocrossing1681d ago

That reminds me, thanks for introducing me to the game Cat! :D

Cat1681d ago

Glad you're having fun with it!

Awais1681d ago

Can't wait to try it out

zerocrossing1681d ago

It's actually pretty fun :)

I'm not a big mobile gamer myself but it's the kind of game you can pick up and play anytime, even for a short while, and feel like you've made at least some progress.

RyanDJ1681d ago

Perhaps I could take a shot at it?

inverse0011681d ago

I sure would like a code!